Base | Representation |
---|---|
bin | 11011010010011001011010… |
… | …001100110100010100110111 |
3 | 120201220222122001021211011101 |
4 | 123102121122030310110313 |
5 | 111212232012302304302 |
6 | 1103124303412350531 |
7 | 34164354405240154 |
oct | 3322313214642467 |
9 | 521828561254141 |
10 | 120011489494327 |
11 | 3526a650143372 |
12 | 11563045015447 |
13 | 51c705b89b622 |
14 | 218c830d5d22b |
15 | dd1b93185287 |
hex | 6d265a334537 |
120011489494327 has 2 divisors, whose sum is σ = 120011489494328. Its totient is φ = 120011489494326.
The previous prime is 120011489494291. The next prime is 120011489494339. The reversal of 120011489494327 is 723494984110021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120011489494327 - 239 = 119461733680439 is a prime.
It is a super-2 number, since 2×1200114894943272 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120011489494367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60005744747163 + 60005744747164.
It is an arithmetic number, because the mean of its divisors is an integer number (60005744747164).
Almost surely, 2120011489494327 is an apocalyptic number.
120011489494327 is a deficient number, since it is larger than the sum of its proper divisors (1).
120011489494327 is an equidigital number, since it uses as much as digits as its factorization.
120011489494327 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3483648, while the sum is 55.
The spelling of 120011489494327 in words is "one hundred twenty trillion, eleven billion, four hundred eighty-nine million, four hundred ninety-four thousand, three hundred twenty-seven".
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