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120012000107 is a prime number
BaseRepresentation
bin110111111000101000…
…1011100101101101011
3102110202211202021112212
41233301101130231223
53431241033000412
6131044401355335
711446003112066
oct1576121345553
9373684667485
10120012000107
1146995710a6a
121b313938b4b
13b41782941c
145b46b8b8dd
1531c6076222
hex1bf145cb6b

120012000107 has 2 divisors, whose sum is σ = 120012000108. Its totient is φ = 120012000106.

The previous prime is 120012000061. The next prime is 120012000109. The reversal of 120012000107 is 701000210021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120012000107 - 222 = 120007805803 is a prime.

It is a super-2 number, since 2×1200120001072 (a number of 23 digits) contains 22 as substring.

Together with 120012000109, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120012000091 and 120012000100.

It is not a weakly prime, because it can be changed into another prime (120012000109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60006000053 + 60006000054.

It is an arithmetic number, because the mean of its divisors is an integer number (60006000054).

Almost surely, 2120012000107 is an apocalyptic number.

120012000107 is a deficient number, since it is larger than the sum of its proper divisors (1).

120012000107 is an equidigital number, since it uses as much as digits as its factorization.

120012000107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 14.

Adding to 120012000107 its reverse (701000210021), we get a palindrome (821012210128).

The spelling of 120012000107 in words is "one hundred twenty billion, twelve million, one hundred seven", and thus it is an aban number.