12001200132023 has 2 divisors, whose sum is σ = 12001200132024. Its totient is φ = 12001200132022.

The previous prime is 12001200132013. The next prime is 12001200132037. The reversal of 12001200132023 is 32023100210021.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12001200132023 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 12001200131992 and 12001200132010.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12001200132013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000600066011 + 6000600066012.

It is an arithmetic number, because the mean of its divisors is an integer number (6000600066012).

Almost surely, 2^{12001200132023} is an apocalyptic number.

12001200132023 is a deficient number, since it is larger than the sum of its proper divisors (1).

12001200132023 is an equidigital number, since it uses as much as digits as its factorization.

12001200132023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 12001200132023 its reverse (32023100210021), we get a palindrome (44024300342044).

The spelling of 12001200132023 in words is "twelve trillion, one billion, two hundred million, one hundred thirty-two thousand, twenty-three".