Base | Representation |
---|---|
bin | 1010111010100100000010… |
… | …1001011001101111111111 |
3 | 1120111022020212210010111011 |
4 | 2232221000221121233333 |
5 | 3033112001121021343 |
6 | 41305141423540051 |
7 | 2346026333141146 |
oct | 256510051315777 |
9 | 46438225703434 |
10 | 12001223220223 |
11 | 3907765700306 |
12 | 1419b0145a627 |
13 | 690930c54133 |
14 | 2d6c1023475d |
15 | 15c2a54e629d |
hex | aea40a59bff |
12001223220223 has 2 divisors, whose sum is σ = 12001223220224. Its totient is φ = 12001223220222.
The previous prime is 12001223220209. The next prime is 12001223220269. The reversal of 12001223220223 is 32202232210021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12001223220223 - 25 = 12001223220191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12001223220194 and 12001223220203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12001223220023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6000611610111 + 6000611610112.
It is an arithmetic number, because the mean of its divisors is an integer number (6000611610112).
Almost surely, 212001223220223 is an apocalyptic number.
12001223220223 is a deficient number, since it is larger than the sum of its proper divisors (1).
12001223220223 is an equidigital number, since it uses as much as digits as its factorization.
12001223220223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1152, while the sum is 22.
Adding to 12001223220223 its reverse (32202232210021), we get a palindrome (44203455430244).
The spelling of 12001223220223 in words is "twelve trillion, one billion, two hundred twenty-three million, two hundred twenty thousand, two hundred twenty-three".
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