12001340112 has 20 divisors (see below), whose sum is σ = 31003462080. Its totient is φ = 4000446688.

The previous prime is 12001340083. The next prime is 12001340137. The reversal of 12001340112 is 21104310021.

It is a junction number, because it is equal to n+sod(n) for n = 12001340091 and 12001340100.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 125013912 + ... + 125014007.

It is an arithmetic number, because the mean of its divisors is an integer number (1550173104).

Almost surely, 2^12001340112 is an apocalyptic number.

12001340112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

12001340112 is an abundant number, since it is smaller than the sum of its proper divisors (19002121968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12001340112 is a wasteful number, since it uses less digits than its factorization.

12001340112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 250027930 (or 250027924 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12001340112 its reverse (21104310021), we get a palindrome (33105650133).

The spelling of 12001340112 in words is "twelve billion, one million, three hundred forty thousand, one hundred twelve".