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120014300114089 is a prime number
BaseRepresentation
bin11011010010011100000001…
…101110011110110010101001
3120201221020212220222002122121
4123102130001232132302221
5111212303241312122324
61103125450333551241
734164514144145653
oct3322340156366251
9521836786862577
10120014300114089
1135270862714617
12115636aa345521
1351c73b8c76544
14218ca1a3496d3
15dd1ca9cbb5e4
hex6d2701b9eca9

120014300114089 has 2 divisors, whose sum is σ = 120014300114090. Its totient is φ = 120014300114088.

The previous prime is 120014300113993. The next prime is 120014300114161. The reversal of 120014300114089 is 980411003410021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88952437731600 + 31061862382489 = 9431460^2 + 5573317^2 .

It is a cyclic number.

It is not a de Polignac number, because 120014300114089 - 223 = 120014291725481 is a prime.

It is not a weakly prime, because it can be changed into another prime (120014300114389) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60007150057044 + 60007150057045.

It is an arithmetic number, because the mean of its divisors is an integer number (60007150057045).

Almost surely, 2120014300114089 is an apocalyptic number.

It is an amenable number.

120014300114089 is a deficient number, since it is larger than the sum of its proper divisors (1).

120014300114089 is an equidigital number, since it uses as much as digits as its factorization.

120014300114089 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 34.

The spelling of 120014300114089 in words is "one hundred twenty trillion, fourteen billion, three hundred million, one hundred fourteen thousand, eighty-nine".