Base | Representation |
---|---|
bin | 110111111000110111… |
… | …1001110000011101001 |
3 | 102110210101102210000111 |
4 | 1233301233032003221 |
5 | 3431300032220033 |
6 | 131045240534321 |
7 | 11446126335106 |
oct | 1576157160351 |
9 | 373711383014 |
10 | 120019804393 |
11 | 4699a061495 |
12 | 1b3164813a1 |
13 | b41932c748 |
14 | 5b47c1daad |
15 | 31c6ab87cd |
hex | 1bf1bce0e9 |
120019804393 has 2 divisors, whose sum is σ = 120019804394. Its totient is φ = 120019804392.
The previous prime is 120019804369. The next prime is 120019804433. The reversal of 120019804393 is 393408910021.
It is an a-pointer prime, because the next prime (120019804433) can be obtained adding 120019804393 to its sum of digits (40).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 76103153424 + 43916650969 = 275868^2 + 209563^2 .
It is a cyclic number.
It is not a de Polignac number, because 120019804393 - 25 = 120019804361 is a prime.
It is not a weakly prime, because it can be changed into another prime (120019804493) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60009902196 + 60009902197.
It is an arithmetic number, because the mean of its divisors is an integer number (60009902197).
Almost surely, 2120019804393 is an apocalyptic number.
It is an amenable number.
120019804393 is a deficient number, since it is larger than the sum of its proper divisors (1).
120019804393 is an equidigital number, since it uses as much as digits as its factorization.
120019804393 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 46656, while the sum is 40.
The spelling of 120019804393 in words is "one hundred twenty billion, nineteen million, eight hundred four thousand, three hundred ninety-three".
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