Base | Representation |
---|---|
bin | 11011010010100001010101… |
… | …011101111011010111001011 |
3 | 120201221210121011100201202012 |
4 | 123102201111131323113023 |
5 | 111212401430001344412 |
6 | 1103132232110530135 |
7 | 34165105325466044 |
oct | 3322412535732713 |
9 | 521853534321665 |
10 | 120020000028107 |
11 | 35273218112363 |
12 | 1156481b20694b |
13 | 51c7ab6b1432a |
14 | 218cddb3618cb |
15 | dd1ee03c9c22 |
hex | 6d285577b5cb |
120020000028107 has 2 divisors, whose sum is σ = 120020000028108. Its totient is φ = 120020000028106.
The previous prime is 120020000028077. The next prime is 120020000028109. The reversal of 120020000028107 is 701820000020021.
It is a strong prime.
It is an emirp because it is prime and its reverse (701820000020021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120020000028107 is a prime.
Together with 120020000028109, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (120020000028109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010000014053 + 60010000014054.
It is an arithmetic number, because the mean of its divisors is an integer number (60010000014054).
Almost surely, 2120020000028107 is an apocalyptic number.
120020000028107 is a deficient number, since it is larger than the sum of its proper divisors (1).
120020000028107 is an equidigital number, since it uses as much as digits as its factorization.
120020000028107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 23.
Adding to 120020000028107 its reverse (701820000020021), we get a palindrome (821840000048128).
The spelling of 120020000028107 in words is "one hundred twenty trillion, twenty billion, twenty-eight thousand, one hundred seven".
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