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120020000028107 is a prime number
BaseRepresentation
bin11011010010100001010101…
…011101111011010111001011
3120201221210121011100201202012
4123102201111131323113023
5111212401430001344412
61103132232110530135
734165105325466044
oct3322412535732713
9521853534321665
10120020000028107
1135273218112363
121156481b20694b
1351c7ab6b1432a
14218cddb3618cb
15dd1ee03c9c22
hex6d285577b5cb

120020000028107 has 2 divisors, whose sum is σ = 120020000028108. Its totient is φ = 120020000028106.

The previous prime is 120020000028077. The next prime is 120020000028109. The reversal of 120020000028107 is 701820000020021.

It is a strong prime.

It is an emirp because it is prime and its reverse (701820000020021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-120020000028107 is a prime.

Together with 120020000028109, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (120020000028109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010000014053 + 60010000014054.

It is an arithmetic number, because the mean of its divisors is an integer number (60010000014054).

Almost surely, 2120020000028107 is an apocalyptic number.

120020000028107 is a deficient number, since it is larger than the sum of its proper divisors (1).

120020000028107 is an equidigital number, since it uses as much as digits as its factorization.

120020000028107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 448, while the sum is 23.

Adding to 120020000028107 its reverse (701820000020021), we get a palindrome (821840000048128).

The spelling of 120020000028107 in words is "one hundred twenty trillion, twenty billion, twenty-eight thousand, one hundred seven".