Base | Representation |
---|---|
bin | 11011010010100010010001… |
… | …000101010111001001110111 |
3 | 120201221220011212101210212122 |
4 | 123102202101011113021313 |
5 | 111212411002024040203 |
6 | 1103132515240310155 |
7 | 34165142162133146 |
oct | 3322422105271167 |
9 | 521856155353778 |
10 | 120021000221303 |
11 | 35273690758305 |
12 | 11564a5a17235b |
13 | 51c7c160bb41c |
14 | 218d09411d75d |
15 | dd204d0e8538 |
hex | 6d2891157277 |
120021000221303 has 2 divisors, whose sum is σ = 120021000221304. Its totient is φ = 120021000221302.
The previous prime is 120021000221279. The next prime is 120021000221359. The reversal of 120021000221303 is 303122000120021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120021000221303 is a prime.
It is a super-3 number, since 3×1200210002213033 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120021000221803) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010500110651 + 60010500110652.
It is an arithmetic number, because the mean of its divisors is an integer number (60010500110652).
Almost surely, 2120021000221303 is an apocalyptic number.
120021000221303 is a deficient number, since it is larger than the sum of its proper divisors (1).
120021000221303 is an equidigital number, since it uses as much as digits as its factorization.
120021000221303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 120021000221303 its reverse (303122000120021), we get a palindrome (423143000341324).
The spelling of 120021000221303 in words is "one hundred twenty trillion, twenty-one billion, two hundred twenty-one thousand, three hundred three".
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