120021001000993 has 2 divisors, whose sum is σ = 120021001000994. Its totient is φ = 120021001000992.

The previous prime is 120021001000963. The next prime is 120021001001039. The reversal of 120021001000993 is 399000100120021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92917492554384 + 27103508446609 = 9639372^2 + 5206103^2 .

It is a cyclic number.

It is not a de Polignac number, because 120021001000993 - 2¹⁷ = 120021000869921 is a prime.

It is not a weakly prime, because it can be changed into another prime (120021001000903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010500500496 + 60010500500497.

It is an arithmetic number, because the mean of its divisors is an integer number (60010500500497).

Almost surely, 2^{120021001000993} is an apocalyptic number.

It is an amenable number.

120021001000993 is a deficient number, since it is larger than the sum of its proper divisors (1).

120021001000993 is an equidigital number, since it uses as much as digits as its factorization.

120021001000993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 120021001000993 in words is "one hundred twenty trillion, twenty-one billion, one million, nine hundred ninety-three", and thus it is an aban number.