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120021021102113 is a prime number
BaseRepresentation
bin11011010010100010010010…
…010101000001000000100001
3120201221220020022200122221222
4123102202102111001000201
5111212411022400231423
61103132521304024425
734165142534461145
oct3322422225010041
9521856208618858
10120021021102113
11352736a151a37a
1211564a65162115
1351c7c1a51c731
14218d096bd7225
15dd204ed703c8
hex6d2892541021

120021021102113 has 2 divisors, whose sum is σ = 120021021102114. Its totient is φ = 120021021102112.

The previous prime is 120021021102097. The next prime is 120021021102173. The reversal of 120021021102113 is 311201120120021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97021160404624 + 22999860697489 = 9849932^2 + 4795817^2 .

It is a cyclic number.

It is not a de Polignac number, because 120021021102113 - 24 = 120021021102097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 120021021102091 and 120021021102100.

It is not a weakly prime, because it can be changed into another prime (120021021102173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010510551056 + 60010510551057.

It is an arithmetic number, because the mean of its divisors is an integer number (60010510551057).

Almost surely, 2120021021102113 is an apocalyptic number.

It is an amenable number.

120021021102113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120021021102113 is an equidigital number, since it uses as much as digits as its factorization.

120021021102113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 120021021102113 its reverse (311201120120021), we get a palindrome (431222141222134).

The spelling of 120021021102113 in words is "one hundred twenty trillion, twenty-one billion, twenty-one million, one hundred two thousand, one hundred thirteen".