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1200211000013 is a prime number
BaseRepresentation
bin10001011101110010001…
…001100111101011001101
311020201221202202000120202
4101131302021213223031
5124131013004000023
62315211435023245
7152466230113304
oct21356211475315
94221852660522
101200211000013
11423008902573
1217473829ab25
1389244223a9c
144213a57143b
15213484b9128
hex11772267acd

1200211000013 has 2 divisors, whose sum is σ = 1200211000014. Its totient is φ = 1200211000012.

The previous prime is 1200210999989. The next prime is 1200211000031. The reversal of 1200211000013 is 3100001120021.

Together with next prime (1200211000031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1141260616804 + 58950383209 = 1068298^2 + 242797^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1200211000013 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1200210999958 and 1200211000003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200211000073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600105500006 + 600105500007.

It is an arithmetic number, because the mean of its divisors is an integer number (600105500007).

Almost surely, 21200211000013 is an apocalyptic number.

It is an amenable number.

1200211000013 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200211000013 is an equidigital number, since it uses as much as digits as its factorization.

1200211000013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12, while the sum is 11.

Adding to 1200211000013 its reverse (3100001120021), we get a palindrome (4300212120034).

The spelling of 1200211000013 in words is "one trillion, two hundred billion, two hundred eleven million, thirteen", and thus it is an aban number.