12002111331307 has 2 divisors, whose sum is σ = 12002111331308. Its totient is φ = 12002111331306.

The previous prime is 12002111331263. The next prime is 12002111331401. The reversal of 12002111331307 is 70313311120021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12002111331307 - 2⁴³ = 3206018309099 is a prime.

It is not a weakly prime, because it can be changed into another prime (12002111335307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001055665653 + 6001055665654.

It is an arithmetic number, because the mean of its divisors is an integer number (6001055665654).

Almost surely, 2^{12002111331307} is an apocalyptic number.

12002111331307 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002111331307 is an equidigital number, since it uses as much as digits as its factorization.

12002111331307 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 12002111331307 its reverse (70313311120021), we get a palindrome (82315422451328).

The spelling of 12002111331307 in words is "twelve trillion, two billion, one hundred eleven million, three hundred thirty-one thousand, three hundred seven".