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12002131411 is a prime number
BaseRepresentation
bin10110010110110000…
…11111110111010011
31010222110010110002121
423023120133313103
5144040021201121
65302543155111
7603265301524
oct131330376723
933873113077
1012002131411
1150a9987a76
1223ab5a5a97
13119372ca0a
1481c01484b
154a3a42141
hex2cb61fdd3

12002131411 has 2 divisors, whose sum is σ = 12002131412. Its totient is φ = 12002131410.

The previous prime is 12002131409. The next prime is 12002131457. The reversal of 12002131411 is 11413120021.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 12002131411 - 21 = 12002131409 is a prime.

Together with 12002131409, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (12002131481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001065705 + 6001065706.

It is an arithmetic number, because the mean of its divisors is an integer number (6001065706).

Almost surely, 212002131411 is an apocalyptic number.

12002131411 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002131411 is an equidigital number, since it uses as much as digits as its factorization.

12002131411 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 12002131411 its reverse (11413120021), we get a palindrome (23415251432).

The spelling of 12002131411 in words is "twelve billion, two million, one hundred thirty-one thousand, four hundred eleven".