Base | Representation |
---|---|
bin | 10110010110110000… |
… | …11111110111010011 |
3 | 1010222110010110002121 |
4 | 23023120133313103 |
5 | 144040021201121 |
6 | 5302543155111 |
7 | 603265301524 |
oct | 131330376723 |
9 | 33873113077 |
10 | 12002131411 |
11 | 50a9987a76 |
12 | 23ab5a5a97 |
13 | 119372ca0a |
14 | 81c01484b |
15 | 4a3a42141 |
hex | 2cb61fdd3 |
12002131411 has 2 divisors, whose sum is σ = 12002131412. Its totient is φ = 12002131410.
The previous prime is 12002131409. The next prime is 12002131457. The reversal of 12002131411 is 11413120021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12002131411 - 21 = 12002131409 is a prime.
Together with 12002131409, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (12002131481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001065705 + 6001065706.
It is an arithmetic number, because the mean of its divisors is an integer number (6001065706).
Almost surely, 212002131411 is an apocalyptic number.
12002131411 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002131411 is an equidigital number, since it uses as much as digits as its factorization.
12002131411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12002131411 its reverse (11413120021), we get a palindrome (23415251432).
The spelling of 12002131411 in words is "twelve billion, two million, one hundred thirty-one thousand, four hundred eleven".
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