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120021413137 is a prime number
BaseRepresentation
bin110111111000111010…
…1010110110100010001
3102110210111110111210121
41233301311112310101
53431300440210022
6131045335230241
711446146115243
oct1576165266421
9373714414717
10120021413137
114699aa6012a
121b316b18381
13b419773a72
145b4811c093
1531c6cd52c7
hex1bf1d56d11

120021413137 has 2 divisors, whose sum is σ = 120021413138. Its totient is φ = 120021413136.

The previous prime is 120021413009. The next prime is 120021413167. The reversal of 120021413137 is 731314120021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120021366481 + 46656 = 346441^2 + 216^2 .

It is a cyclic number.

It is not a de Polignac number, because 120021413137 - 27 = 120021413009 is a prime.

It is a super-2 number, since 2×1200214131372 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (120021413167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60010706568 + 60010706569.

It is an arithmetic number, because the mean of its divisors is an integer number (60010706569).

Almost surely, 2120021413137 is an apocalyptic number.

It is an amenable number.

120021413137 is a deficient number, since it is larger than the sum of its proper divisors (1).

120021413137 is an equidigital number, since it uses as much as digits as its factorization.

120021413137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 120021413137 its reverse (731314120021), we get a palindrome (851335533158).

The spelling of 120021413137 in words is "one hundred twenty billion, twenty-one million, four hundred thirteen thousand, one hundred thirty-seven".