Base | Representation |
---|---|
bin | 101101110010… |
… | …001101100011 |
3 | 211120202211222 |
4 | 231302031203 |
5 | 11033032042 |
6 | 1105125255 |
7 | 204005453 |
oct | 55621543 |
9 | 24522758 |
10 | 12002147 |
11 | 6858433 |
12 | 402982b |
13 | 2642c81 |
14 | 1845d63 |
15 | 10c12d2 |
hex | b72363 |
12002147 has 2 divisors, whose sum is σ = 12002148. Its totient is φ = 12002146.
The previous prime is 12002093. The next prime is 12002161. The reversal of 12002147 is 74120021.
It is a strong prime.
It is an emirp because it is prime and its reverse (74120021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12002147 - 214 = 11985763 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12002647) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001073 + 6001074.
It is an arithmetic number, because the mean of its divisors is an integer number (6001074).
Almost surely, 212002147 is an apocalyptic number.
12002147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002147 is an equidigital number, since it uses as much as digits as its factorization.
12002147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 17.
The square root of 12002147 is about 3464.4114940347. The cubic root of 12002147 is about 228.9565015935.
Adding to 12002147 its reverse (74120021), we get a palindrome (86122168).
The spelling of 12002147 in words is "twelve million, two thousand, one hundred forty-seven".
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