Base | Representation |
---|---|
bin | 1010111010100111101011… |
… | …1000110010010000101111 |
3 | 1120111101202222101111220201 |
4 | 2232221322320302100233 |
5 | 3033121001241100221 |
6 | 41305422410454331 |
7 | 2346062466351421 |
oct | 256517270622057 |
9 | 46441688344821 |
10 | 12002200331311 |
11 | 3908117210333 |
12 | 141a1347343a7 |
13 | 690a58508c88 |
14 | 2d6ca3d04811 |
15 | 15c3111a5891 |
hex | aea7ae3242f |
12002200331311 has 2 divisors, whose sum is σ = 12002200331312. Its totient is φ = 12002200331310.
The previous prime is 12002200331293. The next prime is 12002200331353. The reversal of 12002200331311 is 11313300220021.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12002200331311 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12002200331371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001100165655 + 6001100165656.
It is an arithmetic number, because the mean of its divisors is an integer number (6001100165656).
Almost surely, 212002200331311 is an apocalyptic number.
12002200331311 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002200331311 is an equidigital number, since it uses as much as digits as its factorization.
12002200331311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 12002200331311 its reverse (11313300220021), we get a palindrome (23315500551332).
The spelling of 12002200331311 in words is "twelve trillion, two billion, two hundred million, three hundred thirty-one thousand, three hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •