Base | Representation |
---|---|
bin | 1010111010100111101011… |
… | …1111111101001101001011 |
3 | 1120111101210002221000120021 |
4 | 2232221322333331031023 |
5 | 3033121002231224042 |
6 | 41305422515041311 |
7 | 2346062521341121 |
oct | 256517277751513 |
9 | 46441702830507 |
10 | 12002202211147 |
11 | 3908118284715 |
12 | 141a1352a0237 |
13 | 690a58a167c5 |
14 | 2d6ca4273911 |
15 | 15c311427867 |
hex | aea7affd34b |
12002202211147 has 2 divisors, whose sum is σ = 12002202211148. Its totient is φ = 12002202211146.
The previous prime is 12002202211133. The next prime is 12002202211187. The reversal of 12002202211147 is 74111220220021.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12002202211147 - 211 = 12002202209099 is a prime.
It is not a weakly prime, because it can be changed into another prime (12002202211187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001101105573 + 6001101105574.
It is an arithmetic number, because the mean of its divisors is an integer number (6001101105574).
Almost surely, 212002202211147 is an apocalyptic number.
12002202211147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12002202211147 is an equidigital number, since it uses as much as digits as its factorization.
12002202211147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 896, while the sum is 25.
Adding to 12002202211147 its reverse (74111220220021), we get a palindrome (86113422431168).
The spelling of 12002202211147 in words is "twelve trillion, two billion, two hundred two million, two hundred eleven thousand, one hundred forty-seven".
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