Base | Representation |
---|---|
bin | 10001011101110010101… |
… | …101100110101110110010 |
3 | 11020201222102111021122212 |
4 | 101131302231212232302 |
5 | 124131022412331310 |
6 | 2315212413132122 |
7 | 152466403232552 |
oct | 21356255465662 |
9 | 4221872437585 |
10 | 1200220433330 |
11 | 4230131659a6 |
12 | 17473b48a042 |
13 | 89246177729 |
14 | 4213b909162 |
15 | 2134922e205 |
hex | 11772b66bb2 |
1200220433330 has 64 divisors (see below), whose sum is σ = 2238949544832. Its totient is φ = 462879982080.
The previous prime is 1200220433281. The next prime is 1200220433339. The reversal of 1200220433330 is 333340220021.
It is a junction number, because it is equal to n+sod(n) for n = 1200220433296 and 1200220433305.
It is not an unprimeable number, because it can be changed into a prime (1200220433339) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 28923257 + ... + 28964723.
It is an arithmetic number, because the mean of its divisors is an integer number (34983586638).
Almost surely, 21200220433330 is an apocalyptic number.
1200220433330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1200220433330 is a deficient number, since it is larger than the sum of its proper divisors (1038729111502).
1200220433330 is a wasteful number, since it uses less digits than its factorization.
1200220433330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42219.
The product of its (nonzero) digits is 2592, while the sum is 23.
Adding to 1200220433330 its reverse (333340220021), we get a palindrome (1533560653351).
The spelling of 1200220433330 in words is "one trillion, two hundred billion, two hundred twenty million, four hundred thirty-three thousand, three hundred thirty".
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