Base | Representation |
---|---|
bin | 11011010010100100010000… |
… | …000010110000011010101111 |
3 | 120201222002200022102012210011 |
4 | 123102210100002300122233 |
5 | 111212424332320313113 |
6 | 1103133510450154051 |
7 | 34165246025054143 |
oct | 3322442002603257 |
9 | 521862608365704 |
10 | 120023130244783 |
11 | 35274584032497 |
12 | 11565353582927 |
13 | 51c819548bb4c |
14 | 218d216d83223 |
15 | dd21250e163d |
hex | 6d29100b06af |
120023130244783 has 2 divisors, whose sum is σ = 120023130244784. Its totient is φ = 120023130244782.
The previous prime is 120023130244711. The next prime is 120023130244813. The reversal of 120023130244783 is 387442031320021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120023130244783 - 225 = 120023096690351 is a prime.
It is a super-3 number, since 3×1200231302447833 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120023130244583) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60011565122391 + 60011565122392.
It is an arithmetic number, because the mean of its divisors is an integer number (60011565122392).
Almost surely, 2120023130244783 is an apocalyptic number.
120023130244783 is a deficient number, since it is larger than the sum of its proper divisors (1).
120023130244783 is an equidigital number, since it uses as much as digits as its factorization.
120023130244783 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 193536, while the sum is 40.
The spelling of 120023130244783 in words is "one hundred twenty trillion, twenty-three billion, one hundred thirty million, two hundred forty-four thousand, seven hundred eighty-three".
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