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12002346215437 is a prime number
BaseRepresentation
bin1010111010101000001110…
…0101010010100000001101
31120111102011010220012022111
42232222003211102200031
53033121301112343222
641305445101344021
72346066220346524
oct256520345224015
946442133805274
1012002346215437
1139081915a1226
12141a175568011
13690a7c7c6646
142d6cb943b4bb
1515c31ddc0777
hexaea8395280d

12002346215437 has 2 divisors, whose sum is σ = 12002346215438. Its totient is φ = 12002346215436.

The previous prime is 12002346215407. The next prime is 12002346215471. The reversal of 12002346215437 is 73451264320021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6669068662116 + 5333277553321 = 2582454^2 + 2309389^2 .

It is a cyclic number.

It is not a de Polignac number, because 12002346215437 - 231 = 12000198731789 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12002346215437.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12002346215407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001173107718 + 6001173107719.

It is an arithmetic number, because the mean of its divisors is an integer number (6001173107719).

Almost surely, 212002346215437 is an apocalyptic number.

It is an amenable number.

12002346215437 is a deficient number, since it is larger than the sum of its proper divisors (1).

12002346215437 is an equidigital number, since it uses as much as digits as its factorization.

12002346215437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 241920, while the sum is 40.

The spelling of 12002346215437 in words is "twelve trillion, two billion, three hundred forty-six million, two hundred fifteen thousand, four hundred thirty-seven".