Base | Representation |
---|---|
bin | 1010111010101000110111… |
… | …1100010110101101010010 |
3 | 1120111102121020222002201212 |
4 | 2232222031330112231102 |
5 | 3033122130112043010 |
6 | 41305514231100122 |
7 | 2346103430651543 |
oct | 256521574265522 |
9 | 46442536862655 |
10 | 12002520034130 |
11 | 390827072183a |
12 | 141a203811642 |
13 | 690aa9814b42 |
14 | 2d6cd45664ca |
15 | 15c32e2a7505 |
hex | aea8df16b52 |
12002520034130 has 32 divisors (see below), whose sum is σ = 21878440101504. Its totient is φ = 4740212452096.
The previous prime is 12002520034129. The next prime is 12002520034159. The reversal of 12002520034130 is 3143002520021.
It is a super-3 number, since 3×120025200341303 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12002520034096 and 12002520034105.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3165527 + ... + 5833146.
It is an arithmetic number, because the mean of its divisors is an integer number (683701253172).
Almost surely, 212002520034130 is an apocalyptic number.
12002520034130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12002520034130 is a deficient number, since it is larger than the sum of its proper divisors (9875920067374).
12002520034130 is a wasteful number, since it uses less digits than its factorization.
12002520034130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9000370.
The product of its (nonzero) digits is 1440, while the sum is 23.
Adding to 12002520034130 its reverse (3143002520021), we get a palindrome (15145522554151).
The spelling of 12002520034130 in words is "twelve trillion, two billion, five hundred twenty million, thirty-four thousand, one hundred thirty".
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