Base | Representation |
---|---|
bin | 10001011101111000110… |
… | …001011011101110000111 |
3 | 11020202020111210111020220 |
4 | 101131320301123232013 |
5 | 124131224424200403 |
6 | 2315230444155423 |
7 | 152502046336260 |
oct | 21357061335607 |
9 | 4222214714226 |
10 | 1200322100103 |
11 | 423065595725 |
12 | 174769538b73 |
13 | 89261252a99 |
14 | 4214b211967 |
15 | 21353112953 |
hex | 11778c5bb87 |
1200322100103 has 64 divisors (see below), whose sum is σ = 1984535562240. Its totient is φ = 629601177600.
The previous prime is 1200322100101. The next prime is 1200322100119. The reversal of 1200322100103 is 3010012230021.
It is not a de Polignac number, because 1200322100103 - 21 = 1200322100101 is a prime.
It is a super-3 number, since 3×12003221001033 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200322100101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 51818038 + ... + 51841196.
It is an arithmetic number, because the mean of its divisors is an integer number (31008368160).
Almost surely, 21200322100103 is an apocalyptic number.
1200322100103 is a deficient number, since it is larger than the sum of its proper divisors (784213462137).
1200322100103 is a wasteful number, since it uses less digits than its factorization.
1200322100103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26768.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 1200322100103 its reverse (3010012230021), we get a palindrome (4210334330124).
The spelling of 1200322100103 in words is "one trillion, two hundred billion, three hundred twenty-two million, one hundred thousand, one hundred three".
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