Base | Representation |
---|---|
bin | 1010111010101011011111… |
… | …0011011001111010001111 |
3 | 1120111111102012110110221220 |
4 | 2232222313303121322033 |
5 | 3033130044404043043 |
6 | 41310112035454423 |
7 | 2346130016250420 |
oct | 256526763317217 |
9 | 46444365413856 |
10 | 12003222331023 |
11 | 39085a109a8a0 |
12 | 141a37aa57413 |
13 | 690b8c179831 |
14 | 2d6d5d93b647 |
15 | 15c370c80483 |
hex | aeab7cd9e8f |
12003222331023 has 32 divisors (see below), whose sum is σ = 19955606894592. Its totient is φ = 6234753189600.
The previous prime is 12003222331013. The next prime is 12003222331043. The reversal of 12003222331023 is 32013322230021.
It is not a de Polignac number, because 12003222331023 - 217 = 12003222199951 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12003222330984 and 12003222331002.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12003222331013) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 757861 + ... + 4957902.
It is an arithmetic number, because the mean of its divisors is an integer number (623612715456).
Almost surely, 212003222331023 is an apocalyptic number.
12003222331023 is a deficient number, since it is larger than the sum of its proper divisors (7952384563569).
12003222331023 is a wasteful number, since it uses less digits than its factorization.
12003222331023 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5724875.
The product of its (nonzero) digits is 2592, while the sum is 24.
Adding to 12003222331023 its reverse (32013322230021), we get a palindrome (44016544561044).
It can be divided in two parts, 1200 and 3222331023, that added together give a palindrome (3222332223).
The spelling of 12003222331023 in words is "twelve trillion, three billion, two hundred twenty-two million, three hundred thirty-one thousand, twenty-three".
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