1200323310132 has 48 divisors (see below), whose sum is σ = 2803900760640. Its totient is φ = 399658451712.

The previous prime is 1200323310119. The next prime is 1200323310143. The reversal of 1200323310132 is 2310133230021.

It is a junction number, because it is equal to n+sod(n) for n = 1200323310099 and 1200323310108.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 108847603 + ... + 108858629.

It is an arithmetic number, because the mean of its divisors is an integer number (58414599180).

Almost surely, 2^{1200323310132} is an apocalyptic number.

1200323310132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

1200323310132 is an abundant number, since it is smaller than the sum of its proper divisors (1603577450508).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1200323310132 is a wasteful number, since it uses less digits than its factorization.

1200323310132 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20400 (or 20398 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 21.

Adding to 1200323310132 its reverse (2310133230021), we get a palindrome (3510456540153).

The spelling of 1200323310132 in words is "one trillion, two hundred billion, three hundred twenty-three million, three hundred ten thousand, one hundred thirty-two".