120033011013120 has 640 divisors, whose sum is σ = 441857158617600. Its totient is φ = 30849867546624.

The previous prime is 120033011013109. The next prime is 120033011013143. The reversal of 120033011013120 is 21310110330021.

120033011013120 is a `hidden beast` number, since 1 + 20 + 0 + 330 + 1 + 1 + 0 + 1 + 312 + 0 = 666.

120033011013120 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (640).

It is a super-4 number, since 4×120033011013120⁴ (a number of 57 digits) contains 4444 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 120033011013093 and 120033011013102.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1128469059 + ... + 1128575421.

It is an arithmetic number, because the mean of its divisors is an integer number (690401810340).

Almost surely, 2^{120033011013120} is an apocalyptic number.

120033011013120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 120033011013120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (220928579308800).

120033011013120 is an abundant number, since it is smaller than the sum of its proper divisors (321824147604480).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120033011013120 is a wasteful number, since it uses less digits than its factorization.

120033011013120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106987 (or 106965 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 120033011013120 its reverse (21310110330021), we get a palindrome (141343121343141).

The spelling of 120033011013120 in words is "one hundred twenty trillion, thirty-three billion, eleven million, thirteen thousand, one hundred twenty".