1200341203133 has 2 divisors, whose sum is σ = 1200341203134. Its totient is φ = 1200341203132.

The previous prime is 1200341203129. The next prime is 1200341203283. The reversal of 1200341203133 is 3313021430021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1197531885124 + 2809318009 = 1094318^2 + 53003^2 .

It is a cyclic number.

It is not a de Polignac number, because 1200341203133 - 2² = 1200341203129 is a prime.

It is a super-4 number, since 4×1200341203133⁴ (a number of 49 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1200341203099 and 1200341203108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1200341208133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600170601566 + 600170601567.

It is an arithmetic number, because the mean of its divisors is an integer number (600170601567).

Almost surely, 2^{1200341203133} is an apocalyptic number.

It is an amenable number.

1200341203133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1200341203133 is an equidigital number, since it uses as much as digits as its factorization.

1200341203133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1200341203133 its reverse (3313021430021), we get a palindrome (4513362633154).

The spelling of 1200341203133 in words is "one trillion, two hundred billion, three hundred forty-one million, two hundred three thousand, one hundred thirty-three".