Base | Representation |
---|---|
bin | 1010111010101100001110… |
… | …1010110010110011101100 |
3 | 1120111111221002001020200002 |
4 | 2232223003222302303230 |
5 | 3033131001334302200 |
6 | 41310143510323432 |
7 | 2346134654310341 |
oct | 256530352626354 |
9 | 46444832036602 |
10 | 12003421400300 |
11 | 39086934a7560 |
12 | 141a415659578 |
13 | 690bc14992c5 |
14 | 2d6d7c15a7c8 |
15 | 15c3834a3bd5 |
hex | aeac3ab2cec |
12003421400300 has 72 divisors (see below), whose sum is σ = 28444048131072. Its totient is φ = 4360475592000.
The previous prime is 12003421400291. The next prime is 12003421400323. The reversal of 12003421400300 is 300412430021.
It is a super-3 number, since 3×120034214003003 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4415552 + ... + 6595751.
Almost surely, 212003421400300 is an apocalyptic number.
12003421400300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12003421400300 is an abundant number, since it is smaller than the sum of its proper divisors (16440626730772).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12003421400300 is a wasteful number, since it uses less digits than its factorization.
12003421400300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11012319 (or 11012312 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 12003421400300 its reverse (300412430021), we get a palindrome (12303833830321).
The spelling of 12003421400300 in words is "twelve trillion, three billion, four hundred twenty-one million, four hundred thousand, three hundred".
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