Base | Representation |
---|---|
bin | 11011010010101110110001… |
… | …000010000010110001001101 |
3 | 120202000011211012012022112022 |
4 | 123102232301002002301031 |
5 | 111213120443301433143 |
6 | 1103143015105015525 |
7 | 34166125566001643 |
oct | 3322566102026115 |
9 | 522004735168468 |
10 | 120034421124173 |
11 | 35279348485276 |
12 | 115675849245a5 |
13 | 51c927473ca7a |
14 | 218d9a8731193 |
15 | dd258648c268 |
hex | 6d2bb1082c4d |
120034421124173 has 2 divisors, whose sum is σ = 120034421124174. Its totient is φ = 120034421124172.
The previous prime is 120034421124083. The next prime is 120034421124223. The reversal of 120034421124173 is 371421124430021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 118750646014729 + 1283775109444 = 10897277^2 + 1133038^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120034421124173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120034421124073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60017210562086 + 60017210562087.
It is an arithmetic number, because the mean of its divisors is an integer number (60017210562087).
Almost surely, 2120034421124173 is an apocalyptic number.
It is an amenable number.
120034421124173 is a deficient number, since it is larger than the sum of its proper divisors (1).
120034421124173 is an equidigital number, since it uses as much as digits as its factorization.
120034421124173 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32256, while the sum is 35.
Adding to 120034421124173 its reverse (371421124430021), we get a palindrome (491455545554194).
The spelling of 120034421124173 in words is "one hundred twenty trillion, thirty-four billion, four hundred twenty-one million, one hundred twenty-four thousand, one hundred seventy-three".
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