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12004010024137 is a prime number
BaseRepresentation
bin1010111010101110011011…
…0000001101110011001001
31120111120110002122102202221
42232223212300031303021
53033133203031233022
641310322134454041
72346155362445665
oct256534660156311
946446402572687
1012004010024137
11390896579533a
12141a55a804321
13690c86410b31
142d6dd63c18a5
1515c3b9ec5cc7
hexaeae6c0dcc9

12004010024137 has 2 divisors, whose sum is σ = 12004010024138. Its totient is φ = 12004010024136.

The previous prime is 12004010024129. The next prime is 12004010024261. The reversal of 12004010024137 is 73142001040021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9032302933641 + 2971707090496 = 3005379^2 + 1723864^2 .

It is a cyclic number.

It is not a de Polignac number, because 12004010024137 - 23 = 12004010024129 is a prime.

It is not a weakly prime, because it can be changed into another prime (12004010054137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6002005012068 + 6002005012069.

It is an arithmetic number, because the mean of its divisors is an integer number (6002005012069).

Almost surely, 212004010024137 is an apocalyptic number.

It is an amenable number.

12004010024137 is a deficient number, since it is larger than the sum of its proper divisors (1).

12004010024137 is an equidigital number, since it uses as much as digits as its factorization.

12004010024137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1344, while the sum is 25.

Adding to 12004010024137 its reverse (73142001040021), we get a palindrome (85146011064158).

The spelling of 12004010024137 in words is "twelve trillion, four billion, ten million, twenty-four thousand, one hundred thirty-seven".