12004132301107 has 2 divisors, whose sum is σ = 12004132301108. Its totient is φ = 12004132301106.

The previous prime is 12004132301017. The next prime is 12004132301191. The reversal of 12004132301107 is 70110323140021.

Together with previous prime (12004132301017) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (70110323140021) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12004132301107 - 2³⁹ = 11454376487219 is a prime.

It is not a weakly prime, because it can be changed into another prime (12004132301207) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6002066150553 + 6002066150554.

It is an arithmetic number, because the mean of its divisors is an integer number (6002066150554).

Almost surely, 2^{12004132301107} is an apocalyptic number.

12004132301107 is a deficient number, since it is larger than the sum of its proper divisors (1).

12004132301107 is an equidigital number, since it uses as much as digits as its factorization.

12004132301107 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 12004132301107 its reverse (70110323140021), we get a palindrome (82114455441128).

The spelling of 12004132301107 in words is "twelve trillion, four billion, one hundred thirty-two million, three hundred one thousand, one hundred seven".