120042017 has 2 divisors, whose sum is σ = 120042018. Its totient is φ = 120042016.

The previous prime is 120042011. The next prime is 120042079. The reversal of 120042017 is 710240021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95082001 + 24960016 = 9751^2 + 4996^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-120042017 is a prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 120041986 and 120042004.

It is not a weakly prime, because it can be changed into another prime (120042011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60021008 + 60021009.

It is an arithmetic number, because the mean of its divisors is an integer number (60021009).

Almost surely, 2^120042017 is an apocalyptic number.

It is an amenable number.

120042017 is a deficient number, since it is larger than the sum of its proper divisors (1).

120042017 is an equidigital number, since it uses as much as digits as its factorization.

120042017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 112, while the sum is 17.

The square root of 120042017 is about 10956.3687871484. The cubic root of 120042017 is about 493.2999763888.

Adding to 120042017 its reverse (710240021), we get a palindrome (830282038).

The spelling of 120042017 in words is "one hundred twenty million, forty-two thousand, seventeen".