Base | Representation |
---|---|
bin | 10001011101111110101… |
… | …000100010110110010111 |
3 | 11020202111100211100001021 |
4 | 101131332220202312113 |
5 | 124131430112331203 |
6 | 2315244315542011 |
7 | 152504352220060 |
oct | 21357650426627 |
9 | 4222440740037 |
10 | 1200420433303 |
11 | 423106048933 |
12 | 17479645a907 |
13 | 89278731a00 |
14 | 4215a2cb567 |
15 | 2135ba885bd |
hex | 1177ea22d97 |
1200420433303 has 48 divisors (see below), whose sum is σ = 1490702282496. Its totient is φ = 946500871680.
The previous prime is 1200420433283. The next prime is 1200420433343. The reversal of 1200420433303 is 3033340240021.
It is a de Polignac number, because none of the positive numbers 2k-1200420433303 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1200420433343) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 675531151 + ... + 675532927.
It is an arithmetic number, because the mean of its divisors is an integer number (31056297552).
Almost surely, 21200420433303 is an apocalyptic number.
1200420433303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1200420433303 is a deficient number, since it is larger than the sum of its proper divisors (290281849193).
1200420433303 is a wasteful number, since it uses less digits than its factorization.
1200420433303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3464 (or 3451 counting only the distinct ones).
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 1200420433303 its reverse (3033340240021), we get a palindrome (4233760673324).
The spelling of 1200420433303 in words is "one trillion, two hundred billion, four hundred twenty million, four hundred thirty-three thousand, three hundred three".
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