12005353000335 has 32 divisors (see below), whose sum is σ = 19251501984000. Its totient is φ = 6388545118208.

The previous prime is 12005353000307. The next prime is 12005353000337. The reversal of 12005353000335 is 53300035350021.

It is a cyclic number.

It is not a de Polignac number, because 12005353000335 - 2⁸ = 12005353000079 is a prime.

It is a super-2 number, since 2×12005353000335² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12005353000337) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 80363791 + ... + 80513039.

It is an arithmetic number, because the mean of its divisors is an integer number (601609437000).

Almost surely, 2^{12005353000335} is an apocalyptic number.

12005353000335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

12005353000335 is a deficient number, since it is larger than the sum of its proper divisors (7246148983665).

12005353000335 is a wasteful number, since it uses less digits than its factorization.

12005353000335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 161207.

The product of its (nonzero) digits is 20250, while the sum is 30.

Adding to 12005353000335 its reverse (53300035350021), we get a palindrome (65305388350356).

The spelling of 12005353000335 in words is "twelve trillion, five billion, three hundred fifty-three million, three hundred thirty-five", and thus it is an aban number.