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120054039611393 is a prime number
BaseRepresentation
bin11011010011000001000010…
…011000101000100000000001
3120202002001110102211201122002
4123103001002120220200001
5111213431133120031033
61103200021525153345
734200422006252456
oct3323010230504001
9522061412751562
10120054039611393
11352866a5616078
121156b33ab5b855
1351cb080079aa4
14219090a0a582d
15dd2d339973e8
hex6d3042628801

120054039611393 has 2 divisors, whose sum is σ = 120054039611394. Its totient is φ = 120054039611392.

The previous prime is 120054039611327. The next prime is 120054039611437. The reversal of 120054039611393 is 393116930450021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61857784560784 + 58196255050609 = 7864972^2 + 7628647^2 .

It is a cyclic number.

It is not a de Polignac number, because 120054039611393 - 210 = 120054039610369 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (120054039611593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60027019805696 + 60027019805697.

It is an arithmetic number, because the mean of its divisors is an integer number (60027019805697).

Almost surely, 2120054039611393 is an apocalyptic number.

It is an amenable number.

120054039611393 is a deficient number, since it is larger than the sum of its proper divisors (1).

120054039611393 is an equidigital number, since it uses as much as digits as its factorization.

120054039611393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 524880, while the sum is 47.

The spelling of 120054039611393 in words is "one hundred twenty trillion, fifty-four billion, thirty-nine million, six hundred eleven thousand, three hundred ninety-three".