Base | Representation |
---|---|
bin | 10001011110100001001… |
… | …111101100000011110011 |
3 | 11020210222211111021102111 |
4 | 101132201033230003303 |
5 | 124134122241314422 |
6 | 2315422102030151 |
7 | 152524633040134 |
oct | 21364117540363 |
9 | 4223884437374 |
10 | 1201001119987 |
11 | 423383905389 |
12 | 174918a18357 |
13 | 8933bb278b6 |
14 | 421b3487c8b |
15 | 21392a3da77 |
hex | 117a13ec0f3 |
1201001119987 has 2 divisors, whose sum is σ = 1201001119988. Its totient is φ = 1201001119986.
The previous prime is 1201001119939. The next prime is 1201001120027. The reversal of 1201001119987 is 7899111001021.
It is an a-pointer prime, because the next prime (1201001120027) can be obtained adding 1201001119987 to its sum of digits (40).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201001119987 - 215 = 1201001087219 is a prime.
It is not a weakly prime, because it can be changed into another prime (1201001119937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600500559993 + 600500559994.
It is an arithmetic number, because the mean of its divisors is an integer number (600500559994).
Almost surely, 21201001119987 is an apocalyptic number.
1201001119987 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201001119987 is an equidigital number, since it uses as much as digits as its factorization.
1201001119987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9072, while the sum is 40.
The spelling of 1201001119987 in words is "one trillion, two hundred one billion, one million, one hundred nineteen thousand, nine hundred eighty-seven".
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