Base | Representation |
---|---|
bin | 10001011110100001110… |
… | …010011111011110001111 |
3 | 11020211000110122210111022 |
4 | 101132201302133132033 |
5 | 124134132110242341 |
6 | 2315423025344355 |
7 | 152525103426203 |
oct | 21364162373617 |
9 | 4224013583438 |
10 | 1201010243471 |
11 | 423388a76a55 |
12 | 17491ba980bb |
13 | 893409a04cc |
14 | 421b4780b03 |
15 | 21393741e4b |
hex | 117a1c9f78f |
1201010243471 has 2 divisors, whose sum is σ = 1201010243472. Its totient is φ = 1201010243470.
The previous prime is 1201010243423. The next prime is 1201010243527. The reversal of 1201010243471 is 1743420101021.
It is a weak prime.
It is an emirp because it is prime and its reverse (1743420101021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1201010243471 - 210 = 1201010242447 is a prime.
It is a super-3 number, since 3×12010102434713 (a number of 37 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1201010243471.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1201010249471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600505121735 + 600505121736.
It is an arithmetic number, because the mean of its divisors is an integer number (600505121736).
Almost surely, 21201010243471 is an apocalyptic number.
1201010243471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201010243471 is an equidigital number, since it uses as much as digits as its factorization.
1201010243471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 26.
Adding to 1201010243471 its reverse (1743420101021), we get a palindrome (2944430344492).
The spelling of 1201010243471 in words is "one trillion, two hundred one billion, ten million, two hundred forty-three thousand, four hundred seventy-one".
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