Search a number
-
+
120101100113 is a prime number
BaseRepresentation
bin110111111011010010…
…1010101101001010001
3102111000001102000210002
41233312211111221101
53431431340200423
6131101303215345
711451134335631
oct1576645255121
9374001360702
10120101100113
1146a30a38135
121b339747555
13b430124817
145b549426c1
1531cdcc6228
hex1bf6955a51

120101100113 has 2 divisors, whose sum is σ = 120101100114. Its totient is φ = 120101100112.

The previous prime is 120101100109. The next prime is 120101100139. The reversal of 120101100113 is 311001101021.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97161877264 + 22939222849 = 311708^2 + 151457^2 .

It is a cyclic number.

It is not a de Polignac number, because 120101100113 - 22 = 120101100109 is a prime.

It is a super-2 number, since 2×1201011001132 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 120101100094 and 120101100103.

It is not a weakly prime, because it can be changed into another prime (120101109113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050550056 + 60050550057.

It is an arithmetic number, because the mean of its divisors is an integer number (60050550057).

Almost surely, 2120101100113 is an apocalyptic number.

It is an amenable number.

120101100113 is a deficient number, since it is larger than the sum of its proper divisors (1).

120101100113 is an equidigital number, since it uses as much as digits as its factorization.

120101100113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 11.

Adding to 120101100113 its reverse (311001101021), we get a palindrome (431102201134).

The spelling of 120101100113 in words is "one hundred twenty billion, one hundred one million, one hundred thousand, one hundred thirteen".