Base | Representation |
---|---|
bin | 1010111011000101001001… |
… | …1010000011101001011011 |
3 | 1120112011012021221022122212 |
4 | 2232301102122003221123 |
5 | 3033233201421401021 |
6 | 41313211402305335 |
7 | 2346462515101232 |
oct | 256612232035133 |
9 | 46464167838585 |
10 | 12010111122011 |
11 | 3910506697492 |
12 | 141b781ab824b |
13 | 691719416012 |
14 | 2d74147c9b19 |
15 | 15c62592d85b |
hex | aec52683a5b |
12010111122011 has 2 divisors, whose sum is σ = 12010111122012. Its totient is φ = 12010111122010.
The previous prime is 12010111121951. The next prime is 12010111122013. The reversal of 12010111122011 is 11022111101021.
12010111122011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12010111122011 - 26 = 12010111121947 is a prime.
It is a Sophie Germain prime.
Together with 12010111122013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (12010111122013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005055561005 + 6005055561006.
It is an arithmetic number, because the mean of its divisors is an integer number (6005055561006).
Almost surely, 212010111122011 is an apocalyptic number.
12010111122011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12010111122011 is an equidigital number, since it uses as much as digits as its factorization.
12010111122011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 14.
Adding to 12010111122011 its reverse (11022111101021), we get a palindrome (23032222223032).
The spelling of 12010111122011 in words is "twelve trillion, ten billion, one hundred eleven million, one hundred twenty-two thousand, eleven".
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