Base | Representation |
---|---|
bin | 110111111011010010… |
… | …1011010100010001111 |
3 | 102111000001110001020221 |
4 | 1233312211122202033 |
5 | 3431431341321033 |
6 | 131101303452211 |
7 | 11451134451214 |
oct | 1576645324217 |
9 | 374001401227 |
10 | 120101120143 |
11 | 46a30a51194 |
12 | 1b339757067 |
13 | b430130984 |
14 | 5b54949b0b |
15 | 31cdccc12d |
hex | 1bf695a88f |
120101120143 has 2 divisors, whose sum is σ = 120101120144. Its totient is φ = 120101120142.
The previous prime is 120101120099. The next prime is 120101120147. The reversal of 120101120143 is 341021101021.
It is a strong prime.
It is an emirp because it is prime and its reverse (341021101021) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-120101120143 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120101120147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60050560071 + 60050560072.
It is an arithmetic number, because the mean of its divisors is an integer number (60050560072).
Almost surely, 2120101120143 is an apocalyptic number.
120101120143 is a deficient number, since it is larger than the sum of its proper divisors (1).
120101120143 is an equidigital number, since it uses as much as digits as its factorization.
120101120143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 120101120143 its reverse (341021101021), we get a palindrome (461122221164).
The spelling of 120101120143 in words is "one hundred twenty billion, one hundred one million, one hundred twenty thousand, one hundred forty-three".
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