1201011220117 has 2 divisors, whose sum is σ = 1201011220118. Its totient is φ = 1201011220116.

The previous prime is 1201011220091. The next prime is 1201011220121. The reversal of 1201011220117 is 7110221101021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1181849462641 + 19161757476 = 1087129^2 + 138426^2 .

It is an emirp because it is prime and its reverse (7110221101021) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1201011220117 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1201011220094 and 1201011220103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201011220217) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600505610058 + 600505610059.

It is an arithmetic number, because the mean of its divisors is an integer number (600505610059).

Almost surely, 2^{1201011220117} is an apocalyptic number.

It is an amenable number.

1201011220117 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201011220117 is an equidigital number, since it uses as much as digits as its factorization.

1201011220117 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 56, while the sum is 19.

Adding to 1201011220117 its reverse (7110221101021), we get a palindrome (8311232321138).

The spelling of 1201011220117 in words is "one trillion, two hundred one billion, eleven million, two hundred twenty thousand, one hundred seventeen".