Base | Representation |
---|---|
bin | 11011010011110101001011… |
… | …000101010010111100101011 |
3 | 120202021101221211000211000202 |
4 | 123103311023011102330223 |
5 | 111220340310122042141 |
6 | 1103241440445422415 |
7 | 34204443160541525 |
oct | 3323651305227453 |
9 | 522241854024022 |
10 | 120110020112171 |
11 | 352a8412100951 |
12 | 1157a16286aa0b |
13 | 5203431b4906b |
14 | 21934dabaaa15 |
15 | dd450d3c249b |
hex | 6d3d4b152f2b |
120110020112171 has 2 divisors, whose sum is σ = 120110020112172. Its totient is φ = 120110020112170.
The previous prime is 120110020112143. The next prime is 120110020112177. The reversal of 120110020112171 is 171211020011021.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 120110020112171 - 214 = 120110020095787 is a prime.
It is a super-2 number, since 2×1201100201121712 (a number of 29 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (120110020112177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055010056085 + 60055010056086.
It is an arithmetic number, because the mean of its divisors is an integer number (60055010056086).
Almost surely, 2120110020112171 is an apocalyptic number.
120110020112171 is a deficient number, since it is larger than the sum of its proper divisors (1).
120110020112171 is an equidigital number, since it uses as much as digits as its factorization.
120110020112171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 56, while the sum is 20.
Adding to 120110020112171 its reverse (171211020011021), we get a palindrome (291321040123192).
The spelling of 120110020112171 in words is "one hundred twenty trillion, one hundred ten billion, twenty million, one hundred twelve thousand, one hundred seventy-one".
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