Base | Representation |
---|---|
bin | 10001011110100111001… |
… | …001101110011001101011 |
3 | 11020211020201222002002202 |
4 | 101132213021232121223 |
5 | 124134323124020021 |
6 | 2315440002050415 |
7 | 152530245263366 |
oct | 21364711563153 |
9 | 4224221862082 |
10 | 1201100220011 |
11 | 42342484172a |
12 | 174946049a0b |
13 | 89356514873 |
14 | 421c26c30dd |
15 | 2139b5b6a0b |
hex | 117a726e66b |
1201100220011 has 2 divisors, whose sum is σ = 1201100220012. Its totient is φ = 1201100220010.
The previous prime is 1201100219999. The next prime is 1201100220013. The reversal of 1201100220011 is 1100220011021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1201100220011 - 210 = 1201100218987 is a prime.
Together with 1201100220013, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 1201100219974 and 1201100220001.
It is not a weakly prime, because it can be changed into another prime (1201100220013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600550110005 + 600550110006.
It is an arithmetic number, because the mean of its divisors is an integer number (600550110006).
Almost surely, 21201100220011 is an apocalyptic number.
1201100220011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1201100220011 is an equidigital number, since it uses as much as digits as its factorization.
1201100220011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8, while the sum is 11.
Adding to 1201100220011 its reverse (1100220011021), we get a palindrome (2301320231032).
The spelling of 1201100220011 in words is "one trillion, two hundred one billion, one hundred million, two hundred twenty thousand, eleven".
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