Base | Representation |
---|---|
bin | 10110010111110100… |
… | …10111110001111001 |
3 | 1011000001211120212102 |
4 | 23023322113301321 |
5 | 144044304324233 |
6 | 5303501353145 |
7 | 603433624226 |
oct | 131372276171 |
9 | 34001746772 |
10 | 12011011193 |
11 | 51039a2535 |
12 | 23b25687b5 |
13 | 119551b71c |
14 | 81d28694d |
15 | 4a46e81e8 |
hex | 2cbe97c79 |
12011011193 has 2 divisors, whose sum is σ = 12011011194. Its totient is φ = 12011011192.
The previous prime is 12011011189. The next prime is 12011011223. The reversal of 12011011193 is 39111011021.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7305462784 + 4705548409 = 85472^2 + 68597^2 .
It is an emirp because it is prime and its reverse (39111011021) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12011011193 - 22 = 12011011189 is a prime.
It is not a weakly prime, because it can be changed into another prime (12011011183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005505596 + 6005505597.
It is an arithmetic number, because the mean of its divisors is an integer number (6005505597).
Almost surely, 212011011193 is an apocalyptic number.
It is an amenable number.
12011011193 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011011193 is an equidigital number, since it uses as much as digits as its factorization.
12011011193 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 20.
The spelling of 12011011193 in words is "twelve billion, eleven million, eleven thousand, one hundred ninety-three".
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