Base | Representation |
---|---|
bin | 11011010011110101010110… |
… | …011101111001100010001101 |
3 | 120202021102110010102120020102 |
4 | 123103311112131321202031 |
5 | 111220341203021023203 |
6 | 1103241511431300445 |
7 | 34204451000156552 |
oct | 3323652635714215 |
9 | 522242403376212 |
10 | 120110211111053 |
11 | 352a84aa9a6169 |
12 | 1157a1b681a725 |
13 | 52034625a1357 |
14 | 21935182c8a29 |
15 | dd452004e888 |
hex | 6d3d5677988d |
120110211111053 has 2 divisors, whose sum is σ = 120110211111054. Its totient is φ = 120110211111052.
The previous prime is 120110211111017. The next prime is 120110211111061. The reversal of 120110211111053 is 350111112011021.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 76877771392009 + 43232439719044 = 8767997^2 + 6575138^2 .
It is a cyclic number.
It is not a de Polignac number, because 120110211111053 - 214 = 120110211094669 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (120110211111953) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055105555526 + 60055105555527.
It is an arithmetic number, because the mean of its divisors is an integer number (60055105555527).
Almost surely, 2120110211111053 is an apocalyptic number.
It is an amenable number.
120110211111053 is a deficient number, since it is larger than the sum of its proper divisors (1).
120110211111053 is an equidigital number, since it uses as much as digits as its factorization.
120110211111053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60, while the sum is 20.
Adding to 120110211111053 its reverse (350111112011021), we get a palindrome (470221323122074).
The spelling of 120110211111053 in words is "one hundred twenty trillion, one hundred ten billion, two hundred eleven million, one hundred eleven thousand, fifty-three".
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