1201110020141 has 2 divisors, whose sum is σ = 1201110020142. Its totient is φ = 1201110020140.

The previous prime is 1201110020053. The next prime is 1201110020171. The reversal of 1201110020141 is 1410200111021.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1110842221225 + 90267798916 = 1053965^2 + 300446^2 .

It is a cyclic number.

It is not a de Polignac number, because 1201110020141 - 2¹⁴ = 1201110003757 is a prime.

It is a super-2 number, since 2×1201110020141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1201110020171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 600555010070 + 600555010071.

It is an arithmetic number, because the mean of its divisors is an integer number (600555010071).

Almost surely, 2^{1201110020141} is an apocalyptic number.

It is an amenable number.

1201110020141 is a deficient number, since it is larger than the sum of its proper divisors (1).

1201110020141 is an equidigital number, since it uses as much as digits as its factorization.

1201110020141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 1201110020141 its reverse (1410200111021), we get a palindrome (2611310131162).

The spelling of 1201110020141 in words is "one trillion, two hundred one billion, one hundred ten million, twenty thousand, one hundred forty-one".