120111002022127 has 2 divisors, whose sum is σ = 120111002022128. Its totient is φ = 120111002022126.

The previous prime is 120111002022079. The next prime is 120111002022133. The reversal of 120111002022127 is 721220200111021.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 120111002022127 - 2³¹ = 120108854538479 is a prime.

It is a super-4 number, since 4×120111002022127⁴ (a number of 57 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a junction number, because it is equal to n+sod(n) for n = 120111002022098 and 120111002022107.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (120111002022197) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60055501011063 + 60055501011064.

It is an arithmetic number, because the mean of its divisors is an integer number (60055501011064).

Almost surely, 2^{120111002022127} is an apocalyptic number.

120111002022127 is a deficient number, since it is larger than the sum of its proper divisors (1).

120111002022127 is an equidigital number, since it uses as much as digits as its factorization.

120111002022127 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 224, while the sum is 22.

Adding to 120111002022127 its reverse (721220200111021), we get a palindrome (841331202133148).

The spelling of 120111002022127 in words is "one hundred twenty trillion, one hundred eleven billion, two million, twenty-two thousand, one hundred twenty-seven".