Base | Representation |
---|---|
bin | 1010111011001000110111… |
… | …1101001111101010100111 |
3 | 1120112020202220212211210021 |
4 | 2232302031331033222213 |
5 | 3033242223202431043 |
6 | 41313454452140011 |
7 | 2346526336121032 |
oct | 256621575175247 |
9 | 46466686784707 |
10 | 12011110202023 |
11 | 3910979642049 |
12 | 141ba00607607 |
13 | 6918483c051a |
14 | 2d74ab378019 |
15 | 15c6834cc3ed |
hex | aec8df4faa7 |
12011110202023 has 2 divisors, whose sum is σ = 12011110202024. Its totient is φ = 12011110202022.
The previous prime is 12011110201973. The next prime is 12011110202033. The reversal of 12011110202023 is 32020201111021.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12011110202023 - 241 = 9812086946471 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12011110201988 and 12011110202006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011110202033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005555101011 + 6005555101012.
It is an arithmetic number, because the mean of its divisors is an integer number (6005555101012).
Almost surely, 212011110202023 is an apocalyptic number.
12011110202023 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011110202023 is an equidigital number, since it uses as much as digits as its factorization.
12011110202023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 12011110202023 its reverse (32020201111021), we get a palindrome (44031311313044).
The spelling of 12011110202023 in words is "twelve trillion, eleven billion, one hundred ten million, two hundred two thousand, twenty-three".
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