12011111111081 has 2 divisors, whose sum is σ = 12011111111082. Its totient is φ = 12011111111080.

The previous prime is 12011111111047. The next prime is 12011111111137. The reversal of 12011111111081 is 18011111111021.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10508748558400 + 1502362552681 = 3241720^2 + 1225709^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12011111111081 is a prime.

It is a super-3 number, since 3×12011111111081³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (12011111117081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005555555540 + 6005555555541.

It is an arithmetic number, because the mean of its divisors is an integer number (6005555555541).

Almost surely, 2^{12011111111081} is an apocalyptic number.

It is an amenable number.

12011111111081 is a deficient number, since it is larger than the sum of its proper divisors (1).

12011111111081 is an equidigital number, since it uses as much as digits as its factorization.

12011111111081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 20.

The spelling of 12011111111081 in words is "twelve trillion, eleven billion, one hundred eleven million, one hundred eleven thousand, eighty-one".