Base | Representation |
---|---|
bin | 1010111011001000111000… |
… | …0000101101100110000111 |
3 | 1120112020202222121000201211 |
4 | 2232302032000231212013 |
5 | 3033242223421023142 |
6 | 41313454523432251 |
7 | 2346526346625166 |
oct | 256621600554607 |
9 | 46466688530654 |
10 | 12011111111047 |
11 | 391097a103004 |
12 | 141ba00985687 |
13 | 69184864b1c9 |
14 | 2d74ab5333dd |
15 | 15c68360b917 |
hex | aec8e02d987 |
12011111111047 has 2 divisors, whose sum is σ = 12011111111048. Its totient is φ = 12011111111046.
The previous prime is 12011111110987. The next prime is 12011111111081. The reversal of 12011111111047 is 74011111111021.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12011111111047 is a prime.
It is a super-3 number, since 3×120111111110473 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12011111111147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6005555555523 + 6005555555524.
It is an arithmetic number, because the mean of its divisors is an integer number (6005555555524).
Almost surely, 212011111111047 is an apocalyptic number.
12011111111047 is a deficient number, since it is larger than the sum of its proper divisors (1).
12011111111047 is an equidigital number, since it uses as much as digits as its factorization.
12011111111047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56, while the sum is 22.
Adding to 12011111111047 its reverse (74011111111021), we get a palindrome (86022222222068).
The spelling of 12011111111047 in words is "twelve trillion, eleven billion, one hundred eleven million, one hundred eleven thousand, forty-seven".
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